Problem:
User enters two dates, say start date and end date, then we need to alert him if the start date is greater than end date.
Solution:
Assume we are getting the date to the input field using a datepicker.
First we have to convert the string into Date() object using
var dObj = new Date(year, month, date); (also note: the month value range from 0 to 11)
and we can compare the dates.
Example:
var x = document.formName;
//assume the date format is YYYY/MM/DD
var sDate1 = x.start_date.value;
var sDate = new Date(sDate1.split('/')[0], parseInt((sDate1.split('/')[1])-1), sDate1.split('/')[2]);
var eDate1 = x.end_date.value;
var eDate = new Date(eDate1.split('/')[0], parseInt((eDate1.split('/')[1])-1), eDate1.split('/')[2]);
if(eDate >= sDate)
{
alert("End date is greater than start date; please try again....");
return false;
}
-
Thursday, November 26, 2009
Thursday, November 19, 2009
How to add month, days, years in a date
<?php
$day1 = "2008/10/20";
//add month
$day2 = date("Y/m/d", strtotime("+2 months", strtotime($day1)));
//"2008/12/20"
$day2 = date("Y/m/d", strtotime("+3 months", strtotime($day1)));
//"2009/01/20"
//add days
$day2 = date("Y/m/d", strtotime("+5 days", strtotime($day1))); //"2008/10/25"
$day2 = date("Y/m/d", strtotime("+20 days", strtotime($day1))); //"2008/11/09"
//years
$day2 = date("Y/m/d", strtotime("+2 years", strtotime($day1))); //"2010/10/20"
?>
Also we can add weeks.
$day1 = "2008/10/20";
//add month
$day2 = date("Y/m/d", strtotime("+2 months", strtotime($day1)));
//"2008/12/20"
$day2 = date("Y/m/d", strtotime("+3 months", strtotime($day1)));
//"2009/01/20"
//add days
$day2 = date("Y/m/d", strtotime("+5 days", strtotime($day1))); //"2008/10/25"
$day2 = date("Y/m/d", strtotime("+20 days", strtotime($day1))); //"2008/11/09"
//years
$day2 = date("Y/m/d", strtotime("+2 years", strtotime($day1))); //"2010/10/20"
?>
Also we can add weeks.
Thursday, October 29, 2009
Monday, July 20, 2009
Thursday, June 18, 2009
ajax link on no javascript problem - jquery
Problem:
I use jquery for developing ajax processes.
like $("#myLink").click / load...
if the browser javascript disabled, then the ajax link will not work and the user cant go through the pages in the website...
Solution: http://yensdesign.com/2009/06/safe-ajax-links-using-jquery/
I use jquery for developing ajax processes.
like $("#myLink").click / load...
if the browser javascript disabled, then the ajax link will not work and the user cant go through the pages in the website...
Solution: http://yensdesign.com/2009/06/safe-ajax-links-using-jquery/
Thursday, May 28, 2009
Monday, May 18, 2009
Saturday, May 16, 2009
Simple dropdown menu with jquery
Drop Down Menu with Jquery - with no ul - li
http://beski.wordpress.com/2009/05/15/jquery-simple-dropdown-menu/
http://beski.wordpress.com/2009/05/15/jquery-simple-dropdown-menu/
Wednesday, May 6, 2009
Hidden page problem in ajax - Jquery
Problem in accessing hidden / remote file directly when using ajax...
http://beski.wordpress.com/2009/05/06/hidden-file-problem-in-ajax/
http://beski.wordpress.com/2009/05/06/hidden-file-problem-in-ajax/
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